Armstrong Number in Java

armstrong number java 6 years, 3 months ago

public class Armstrong { int power(int x, long y) { if( y == 0) return 1; else if (y%2 == 0) return power(x, y/2)*power(x, y/2); else return x*power(x, y/2)*power(x, y/2); } int order(int x) { int n = 0; while (x != 0) { n++; x = x/10; } return n; } boolean isArmstrong (int x) { int n = order(x); int temp=x, sum=0; while (temp!=0) { int r = temp%10; sum = sum + power(r,n); temp = temp/10; } return (sum == x); } public static void main(String[] args) { Armstrong ob = new Armstrong(); int x = 153; System.out.println(ob.isArmstrong(x)); x = 1253; System.out.println(ob.isArmstrong(x)); } }

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Armstrong Number in Java

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