This will fetch the information of all the employees whose salary either equals to 40,000 or is greater than that.
CREATE TABLE `user` ( `username` VARCHAR(25) NOT NULL, `email` VARCHAR(150) NOT NULL,
# pip install mysql-connector from mysql import connector
Drop table Table_name;
<?php $servername = "localhost"; $username = "username";
SELECT IFNULL( (SELECT NAME
SELECT BIN(5); SELECT BIN(12);
RENAME USER 'RAJ' @ 'localhost' TO 'AMIT RENAME USER 'PRIYA' @ 'localhost' TO 'DI
ALTER TABLE TABLE_NAME RENAME TO NEW_TAB
ALTER TABLE TABLE_NAME RENAME COLUMN TO
SELECT DEFAULT (COLUMN_NAME) FROM TABLE_
DROP USER 'user' @ 'host';
SET PASSWORD FOR 'user' @ 'localhost' =
ALTER USER user@localhost IDENTIFIED BY
UPDATE USER SET AUTHENTICATION_STRING = WHERE USER = 'USER_NAME' AND HOST = 'LOCALHOST';
CREATE USER 'user_name' @ 'localhost' ID
CREATE USER 'user_name' @ 'localhost' IDENTIFIED BY 'user_name' @ 'localhost' IDENTIFIED BY
SELECT AVG(SALARY) FROM EMPLOYEES; SELECT MAX(column_name)
SELECT DATABASE(); SELECT CURRENT_USER();
SELECT MAX (column_name) FROM table_name WHERE column_name NOT IN (SELECT Max (co
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